(5x-1)^2-(1-3x)^2=16x(x-3)

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Solution for (5x-1)^2-(1-3x)^2=16x(x-3) equation: 



(5x-1)^2-(1-3x)^2=16x(x-3)

We move all terms to the left:

(5x-1)^2-(1-3x)^2-(16x(x-3))=0

We add all the numbers together, and all the variables

(5x-1)^2-(-3x+1)^2-(16x(x-3))=0



We calculate terms in parentheses: -(16x(x-3)), so:

16x(x-3)

We multiply parentheses

16x^2-48x

Back to the equation:

-(16x^2-48x)



We get rid of parentheses

-16x^2+(5x-1)^2-(-3x+1)^2+48x=0

We add all the numbers together, and all the variables

-16x^2+48x+(5x-1)^2-(-3x+1)^2=0

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